What is the derivative of y=x^{-3} ?

The derivative of y=x^{-3} is -3/(x^4)

What is the first derivative of y=x^{-3} ?

The first derivative of y=x^{-3} is -3/(x^4)

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derivative of

y = x^{- 3}

- \frac{3}{x ^{4}}

Solution steps

\frac{d}{d x} (x^{- 3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 3 x^{- 3 - 1}

Simplify

- 3 x^{- 3 - 1} : - \frac{3}{x ^{4}}

= - \frac{3}{x ^{4}}

(5^{x})^{x}

(\frac{( a + x )}{( a - x )})^{\frac{3}{2}}

\frac{d}{d p} (20 - p)

∣ x + 2 ∣ - 1

\frac{a}{x ^{2}}

What is the derivative of y=x^{-3} ?
The derivative of y=x^{-3} is -3/(x^4)
What is the first derivative of y=x^{-3} ?
The first derivative of y=x^{-3} is -3/(x^4)