What is the derivative of 5x^2sin(x+4x) ?

The derivative of 5x^2sin(x+4x) is 5(2xsin(x)+cos(x)x^2)+4

What is the first derivative of 5x^2sin(x+4x) ?

The first derivative of 5x^2sin(x+4x) is 5(2xsin(x)+cos(x)x^2)+4

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\frac{d}{d x} (5 x^{2} sin (x) + 4 x)

5 (2 x sin (x) + cos (x) x^{2}) + 4

Solution steps

\frac{d}{d x} (5 x^{2} sin (x) + 4 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (5 x^{2} sin (x)) + \frac{d}{d x} (4 x)

\frac{d}{d x} (5 x^{2} sin (x)) = 5 (2 x sin (x) + cos (x) x^{2})

\frac{d}{d x} (4 x) = 4

= 5 (2 x sin (x) + cos (x) x^{2}) + 4

f (x) = \frac{x ^{4} + c _{1}}{4 x ^{2}}

\int 55 - 6 x - x^{2} d x

n \to \infty lim (28 n + 4)

\frac{a x + b}{c x + d}

\int \frac{x}{x ^{2} + 4 x + 4} d x

What is the derivative of 5x^2sin(x+4x) ?
The derivative of 5x^2sin(x+4x) is 5(2xsin(x)+cos(x)x^2)+4
What is the first derivative of 5x^2sin(x+4x) ?
The first derivative of 5x^2sin(x+4x) is 5(2xsin(x)+cos(x)x^2)+4