What is the derivative of (ax+b)/(cx+d) ?

The derivative of (ax+b)/(cx+d) is (-bc+ad)/((cx+d)^2)

What is the first derivative of (ax+b)/(cx+d) ?

The first derivative of (ax+b)/(cx+d) is (-bc+ad)/((cx+d)^2)

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derivative of

\frac{a x + b}{c x + d}

\frac{- b c + a d}{( c x + d ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{a x + b}{c x + d})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( a x + b ) ( c x + d ) - \frac{d}{d x} ( c x + d ) ( a x + b )}{( c x + d ) ^{2}}

\frac{d}{d x} (a x + b) = a

\frac{d}{d x} (c x + d) = c

= \frac{a ( c x + d ) - c ( a x + b )}{( c x + d ) ^{2}}

Expand

a (c x + d) - c (a x + b) : - b c + a d

= \frac{- b c + a d}{( c x + d ) ^{2}}

\int \frac{x}{x ^{2} + 4 x + 4} d x

\frac{d}{d x} (2 x e^{2 x} + 2 x^{2} e^{2 x})

\int a sin (x) d x

\frac{d}{d x} (cos (x^{2} + y^{2}))

y^{2} = 4 x, y = 2 x + 4

What is the derivative of (ax+b)/(cx+d) ?
The derivative of (ax+b)/(cx+d) is (-bc+ad)/((cx+d)^2)
What is the first derivative of (ax+b)/(cx+d) ?
The first derivative of (ax+b)/(cx+d) is (-bc+ad)/((cx+d)^2)