What is the derivative of y=sin(3x-6)*cos(6-2x) ?

The derivative of y=sin(3x-6)*cos(6-2x) is cos(3x-6)*3cos(6-2x)+2sin(6-2x)sin(3x-6)

What is the first derivative of y=sin(3x-6)*cos(6-2x) ?

The first derivative of y=sin(3x-6)*cos(6-2x) is cos(3x-6)*3cos(6-2x)+2sin(6-2x)sin(3x-6)

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derivative of

y = sin (3 x - 6) \cdot cos (6 - 2 x)

cos (3 x - 6) \cdot 3 cos (6 - 2 x) + 2 sin (6 - 2 x) sin (3 x - 6)

Solution steps

\frac{d}{d x} (sin (3 x - 6) cos (6 - 2 x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = sin (3 x - 6), g = cos (6 - 2 x)

= \frac{d}{d x} (sin (3 x - 6)) cos (6 - 2 x) + \frac{d}{d x} (cos (6 - 2 x)) sin (3 x - 6)

\frac{d}{d x} (sin (3 x - 6)) = cos (3 x - 6) \cdot 3

\frac{d}{d x} (cos (6 - 2 x)) = 2 sin (6 - 2 x)

= cos (3 x - 6) \cdot 3 cos (6 - 2 x) + 2 sin (6 - 2 x) sin (3 x - 6)

\frac{1}{y ^{n} - 1}

sin (x^{3} - 2 x^{2})

- sin^{2} (x)

(1 - x)^{- 1}

x^{8} + x^{\frac{1}{8}}

What is the derivative of y=sin(3x-6)*cos(6-2x) ?
The derivative of y=sin(3x-6)*cos(6-2x) is cos(3x-6)*3cos(6-2x)+2sin(6-2x)sin(3x-6)
What is the first derivative of y=sin(3x-6)*cos(6-2x) ?
The first derivative of y=sin(3x-6)*cos(6-2x) is cos(3x-6)*3cos(6-2x)+2sin(6-2x)sin(3x-6)