What is the first derivative of 2x^2+9 ?

The first derivative of 2x^2+9 is 4x

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derivative of 2x^2+9

derivative of

2 x^{2} + 9

4 x

Solution steps

\frac{d}{d x} (2 x^{2} + 9)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) + \frac{d}{d x} (9)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (9) = 0

= 4 x + 0

Simplify

= 4 x

2 x^{2} + 2

sin^{- 2} (x)

\frac{( x + 1 )}{2}

\frac{d}{d t} (2 cos (12 t))

\frac{( x ^{2} - 2 x )}{( x - 1 ) ^{2}}