What is the derivative of 4(t^5)/5-(t^3)/6 ?

The derivative of 4(t^5)/5-(t^3)/6 is 4t^4-(t^2)/2

What is the first derivative of 4(t^5)/5-(t^3)/6 ?

The first derivative of 4(t^5)/5-(t^3)/6 is 4t^4-(t^2)/2

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derivative of

4 \frac{t ^{5}}{5} - \frac{t ^{3}}{6}

4 t^{4} - \frac{t ^{2}}{2}

Solution steps

\frac{d}{d t} (4 \cdot \frac{t ^{5}}{5} - \frac{t ^{3}}{6})

Simplify

4 \cdot \frac{t ^{5}}{5} - \frac{t ^{3}}{6} : \frac{4 t ^{5}}{5} - \frac{t ^{3}}{6}

= \frac{d}{d t} (\frac{4 t ^{5}}{5} - \frac{t ^{3}}{6})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (\frac{4 t ^{5}}{5}) - \frac{d}{d t} (\frac{t ^{3}}{6})

\frac{d}{d t} (\frac{4 t ^{5}}{5}) = 4 t^{4}

\frac{d}{d t} (\frac{t ^{3}}{6}) = \frac{t ^{2}}{2}

= 4 t^{4} - \frac{t ^{2}}{2}

\frac{d}{d q} (\frac{5 + 1}{( cot ( q ) )})

f (x) = 3 cos (x) - 4 sec (x) + 3

\frac{d}{d z} ((8 x^{3} + 3)^{4} x^{5} z^{2})

\frac{10 x + x ^{2}}{2}

f (x) = x \cdot 2 x

What is the derivative of 4(t^5)/5-(t^3)/6 ?
The derivative of 4(t^5)/5-(t^3)/6 is 4t^4-(t^2)/2
What is the first derivative of 4(t^5)/5-(t^3)/6 ?
The first derivative of 4(t^5)/5-(t^3)/6 is 4t^4-(t^2)/2