What is the derivative of e^{x^2+x-1} ?

The derivative of e^{x^2+x-1} is e^{x^2+x-1}(2x+1)

What is the first derivative of e^{x^2+x-1} ?

The first derivative of e^{x^2+x-1} is e^{x^2+x-1}(2x+1)

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derivative of

e^{x^{2} + x - 1}

e^{x^{2} + x - 1} (2 x + 1)

Solution steps

\frac{d}{d x} (e^{x^{2} + x - 1})

Apply the chain rule:

e^{x^{2} + x - 1} \frac{d}{d x} (x^{2} + x - 1)

= e^{x^{2} + x - 1} \frac{d}{d x} (x^{2} + x - 1)

\frac{d}{d x} (x^{2} + x - 1) = 2 x + 1

= e^{x^{2} + x - 1} (2 x + 1)

42 x^{\frac{1}{2}}

\frac{1}{r}

\frac{d}{d n} (\frac{n !}{7 ^{n}})

1 + x tan (x)

3 x^{2} - 5 x^{3} + 4 x^{20}

What is the derivative of e^{x^2+x-1} ?
The derivative of e^{x^2+x-1} is e^{x^2+x-1}(2x+1)
What is the first derivative of e^{x^2+x-1} ?
The first derivative of e^{x^2+x-1} is e^{x^2+x-1}(2x+1)