What is the derivative of 1+xtan(x) ?

The derivative of 1+xtan(x) is xsec^2(x)+tan(x)

What is the first derivative of 1+xtan(x) ?

The first derivative of 1+xtan(x) is xsec^2(x)+tan(x)

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derivative of

1 + x tan (x)

x sec^{2} (x) + tan (x)

Solution steps

\frac{d}{d x} (1 + x tan (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (x tan (x))

\frac{d}{d x} (1) = 0

\frac{d}{d x} (x tan (x)) = tan (x) + x sec^{2} (x)

= 0 + tan (x) + x sec^{2} (x)

Simplify

= x sec^{2} (x) + tan (x)

3 x^{2} - 5 x^{3} + 4 x^{20}

y = e^{4} + ln (x)

3 sin^{2} (x) + 2 tan (x)

(2 x^{2} + 3 x + 2)^{5}

\frac{( x - 1 ) ( x - 3 )}{( x - 2 ) ^{2}}

What is the derivative of 1+xtan(x) ?
The derivative of 1+xtan(x) is xsec^2(x)+tan(x)
What is the first derivative of 1+xtan(x) ?
The first derivative of 1+xtan(x) is xsec^2(x)+tan(x)