What is the derivative of 2^x+2^{-x} ?

The derivative of 2^x+2^{-x} is 2^xln(2)-ln(2)*2^{-x}

What is the first derivative of 2^x+2^{-x} ?

The first derivative of 2^x+2^{-x} is 2^xln(2)-ln(2)*2^{-x}

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derivative of

2^{x} + 2^{- x}

2^{x} ln (2) - ln (2) \cdot 2^{- x}

Solution steps

\frac{d}{d x} (2^{x} + 2^{- x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2^{x}) + \frac{d}{d x} (2^{- x})

\frac{d}{d x} (2^{x}) = 2^{x} ln (2)

\frac{d}{d x} (2^{- x}) = - ln (2) \cdot 2^{- x}

= 2^{x} ln (2) - ln (2) \cdot 2^{- x}

\frac{d}{d x} (tan^{22} (x))

3 \cdot 0. 5^{x}

f (x) = x^{3} - x^{2} + 4, k (x) = - 2

\frac{ln ^{2} ( x )}{x}

(- 1)^{x}

What is the derivative of 2^x+2^{-x} ?
The derivative of 2^x+2^{-x} is 2^xln(2)-ln(2)*2^{-x}
What is the first derivative of 2^x+2^{-x} ?
The first derivative of 2^x+2^{-x} is 2^xln(2)-ln(2)*2^{-x}