What is the derivative of y=(t^3)/3 ?

The derivative of y=(t^3)/3 is t^2

What is the first derivative of y=(t^3)/3 ?

The first derivative of y=(t^3)/3 is t^2

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derivative of

y = \frac{t ^{3}}{3}

t^{2}

Solution steps

\frac{d}{d t} (\frac{t ^{3}}{3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{3} \frac{d}{d t} (t^{3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{3} \cdot 3 t^{3 - 1}

Simplify

\frac{1}{3} \cdot 3 t^{3 - 1} : t^{2}

= t^{2}

6 x^{2} + 3 x^{\frac{3}{4}}

\frac{d}{d n} (i^{2 n + 3})

\frac{d}{d c} (1.8 c + 32)

\frac{x + 2}{x}

\frac{1}{e ^{2} x}

What is the derivative of y=(t^3)/3 ?
The derivative of y=(t^3)/3 is t^2
What is the first derivative of y=(t^3)/3 ?
The first derivative of y=(t^3)/3 is t^2