What is the derivative of y=(x^4+5x^2)^7 ?

The derivative of y=(x^4+5x^2)^7 is 7(x^4+5x^2)^6(4x^3+10x)

What is the first derivative of y=(x^4+5x^2)^7 ?

The first derivative of y=(x^4+5x^2)^7 is 7(x^4+5x^2)^6(4x^3+10x)

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derivative of

y = (x^{4} + 5 x^{2})^{7}

7 (x^{4} + 5 x^{2})^{6} (4 x^{3} + 10 x)

Solution steps

\frac{d}{d x} ((x^{4} + 5 x^{2})^{7})

Apply the chain rule:

7 (x^{4} + 5 x^{2})^{6} \frac{d}{d x} (x^{4} + 5 x^{2})

= 7 (x^{4} + 5 x^{2})^{6} \frac{d}{d x} (x^{4} + 5 x^{2})

\frac{d}{d x} (x^{4} + 5 x^{2}) = 4 x^{3} + 10 x

= 7 (x^{4} + 5 x^{2})^{6} (4 x^{3} + 10 x)

y - x^{2} + 1

6 x^{2} - 1

y = \frac{x + 1}{( x + 2 ) ^{2}}

(x^{2} + 3)^{4} (x^{2} + 5)^{2}

\frac{d}{d t} (50 + 4 t)

What is the derivative of y=(x^4+5x^2)^7 ?
The derivative of y=(x^4+5x^2)^7 is 7(x^4+5x^2)^6(4x^3+10x)
What is the first derivative of y=(x^4+5x^2)^7 ?
The first derivative of y=(x^4+5x^2)^7 is 7(x^4+5x^2)^6(4x^3+10x)