What is the derivative of 3-2x+4x^2 ?

The derivative of 3-2x+4x^2 is 8x-2

What is the first derivative of 3-2x+4x^2 ?

The first derivative of 3-2x+4x^2 is 8x-2

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derivative of

3 - 2 x + 4 x^{2}

8 x - 2

Solution steps

\frac{d}{d x} (3 - 2 x + 4 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3) - \frac{d}{d x} (2 x) + \frac{d}{d x} (4 x^{2})

\frac{d}{d x} (3) = 0

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (4 x^{2}) = 8 x

= 0 - 2 + 8 x

Simplify

= 8 x - 2

2 x^{\frac{- 1}{2}}

1 + 6 x

9 e^{- 3} x^{2}

\frac{x + 1 - 4}{( - x + 3 )}

1 + 7 x

What is the derivative of 3-2x+4x^2 ?
The derivative of 3-2x+4x^2 is 8x-2
What is the first derivative of 3-2x+4x^2 ?
The first derivative of 3-2x+4x^2 is 8x-2