What is the derivative of (t^3)/2 ?

The derivative of (t^3)/2 is (3t^2)/2

What is the first derivative of (t^3)/2 ?

The first derivative of (t^3)/2 is (3t^2)/2

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derivative of

\frac{t ^{3}}{2}

\frac{3 t ^{2}}{2}

Solution steps

\frac{d}{d t} (\frac{t ^{3}}{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{2} \frac{d}{d t} (t^{3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{2} \cdot 3 t^{3 - 1}

Simplify

\frac{1}{2} \cdot 3 t^{3 - 1} : \frac{3 t ^{2}}{2}

= \frac{3 t ^{2}}{2}

y = [x^{2} + (1 - 3 x) 5] 3

2 x^{3} - tan (x)

\frac{d}{d x} (lo g_{10} (x^{2} + y^{2}))

a^{2} + x^{2}

\frac{d}{d x} (\frac{2 \cdot k}{x + d})

What is the derivative of (t^3)/2 ?
The derivative of (t^3)/2 is (3t^2)/2
What is the first derivative of (t^3)/2 ?
The first derivative of (t^3)/2 is (3t^2)/2