What is the derivative of 2x^3-tan(x) ?

The derivative of 2x^3-tan(x) is 6x^2-sec^2(x)

What is the first derivative of 2x^3-tan(x) ?

The first derivative of 2x^3-tan(x) is 6x^2-sec^2(x)

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derivative of

2 x^{3} - tan (x)

6 x^{2} - sec^{2} (x)

Solution steps

\frac{d}{d x} (2 x^{3} - tan (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{3}) - \frac{d}{d x} (tan (x))

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (tan (x)) = sec^{2} (x)

= 6 x^{2} - sec^{2} (x)

\frac{d}{d x} (lo g_{10} (x^{2} + y^{2}))

a^{2} + x^{2}

\frac{d}{d x} (\frac{2 \cdot k}{x + d})

y = 3 sin (3 x + 7)

4 x^{3} - 9 x^{2} + 28 x - 68

What is the derivative of 2x^3-tan(x) ?
The derivative of 2x^3-tan(x) is 6x^2-sec^2(x)
What is the first derivative of 2x^3-tan(x) ?
The first derivative of 2x^3-tan(x) is 6x^2-sec^2(x)