What is the derivative of 3e^x-0.4y ?

The derivative of 3e^x-0.4y is 3e^x-0.4(dy)/(dx)

What is the first derivative of 3e^x-0.4y ?

The first derivative of 3e^x-0.4y is 3e^x-0.4(dy)/(dx)

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\frac{d}{d x} (3 e^{x} - 0.4 y)

3 e^{x} - 0.4 \frac{d y}{d x}

Solution steps

\frac{d}{d x} (3 e^{x} - 0.4 y)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 e^{x}) - \frac{d}{d x} (0.4 y)

\frac{d}{d x} (3 e^{x}) = 3 e^{x}

\frac{d}{d x} (0.4 y) = 0.4 \frac{d y}{d x}

= 3 e^{x} - 0.4 \frac{d y}{d x}

\frac{x ^{1}}{x}

\frac{lo g _{10} ( x )}{x ^{2}}

3 + 4 x^{2}

\frac{d}{d t} (a sin (t) + 1)

3 cos^{- 3} (x)

What is the derivative of 3e^x-0.4y ?
The derivative of 3e^x-0.4y is 3e^x-0.4(dy)/(dx)
What is the first derivative of 3e^x-0.4y ?
The first derivative of 3e^x-0.4y is 3e^x-0.4(dy)/(dx)