What is the derivative of 5t^2-2t ?

The derivative of 5t^2-2t is 10t-2

What is the first derivative of 5t^2-2t ?

The first derivative of 5t^2-2t is 10t-2

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derivative of

5 t^{2} - 2 t

10 t - 2

Solution steps

\frac{d}{d t} (5 t^{2} - 2 t)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (5 t^{2}) - \frac{d}{d t} (2 t)

\frac{d}{d t} (5 t^{2}) = 10 t

\frac{d}{d t} (2 t) = 2

= 10 t - 2

\frac{2 x}{y}

\frac{- 2}{t ^{2}}

\frac{d}{d n} (sin (n) cos (n) + 3 n + 1)

(s^{2} + a)^{- 2}

\frac{3}{( 2 x ^{2} + 5 ) ^{2}}

What is the derivative of 5t^2-2t ?
The derivative of 5t^2-2t is 10t-2
What is the first derivative of 5t^2-2t ?
The first derivative of 5t^2-2t is 10t-2