What is the derivative of (-2)/(t^2) ?

The derivative of (-2)/(t^2) is 4/(t^3)

What is the first derivative of (-2)/(t^2) ?

The first derivative of (-2)/(t^2) is 4/(t^3)

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derivative of

\frac{- 2}{t ^{2}}

\frac{4}{t ^{3}}

Solution steps

\frac{d}{d t} (\frac{- 2}{t ^{2}})

Simplify

\frac{- 2}{t ^{2}} : - \frac{2}{t ^{2}}

= \frac{d}{d t} (- \frac{2}{t ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 2 \frac{d}{d t} (\frac{1}{t ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= - 2 \frac{d}{d t} (t^{- 2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 2 (- 2 t^{- 2 - 1})

Simplify

- 2 (- 2 t^{- 2 - 1}) : \frac{4}{t ^{3}}

= \frac{4}{t ^{3}}

\frac{d}{d n} (sin (n) cos (n) + 3 n + 1)

(s^{2} + a)^{- 2}

\frac{3}{( 2 x ^{2} + 5 ) ^{2}}

2 - x^{2}

y = lo g_{4} (x^{2})

What is the derivative of (-2)/(t^2) ?
The derivative of (-2)/(t^2) is 4/(t^3)
What is the first derivative of (-2)/(t^2) ?
The first derivative of (-2)/(t^2) is 4/(t^3)