What is the derivative of 2x^4-x^2 ?

The derivative of 2x^4-x^2 is 8x^3-2x

What is the first derivative of 2x^4-x^2 ?

The first derivative of 2x^4-x^2 is 8x^3-2x

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derivative of

2 x^{4} - x^{2}

8 x^{3} - 2 x

Solution steps

\frac{d}{d x} (2 x^{4} - x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{4}) - \frac{d}{d x} (x^{2})

\frac{d}{d x} (2 x^{4}) = 8 x^{3}

\frac{d}{d x} (x^{2}) = 2 x

= 8 x^{3} - 2 x

\frac{1}{tan ^{2} ( x )}

e (x^{2})

\frac{d}{d p} (210 + 16 p)

y = (x^{2} + 1) \cdot (x + 1)

\frac{( 2 + x )}{( 2 - x )}

What is the derivative of 2x^4-x^2 ?
The derivative of 2x^4-x^2 is 8x^3-2x
What is the first derivative of 2x^4-x^2 ?
The first derivative of 2x^4-x^2 is 8x^3-2x