What is the first d/(dp)(210+16p) ?

The first d/(dp)(210+16p) is 16

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d/(dp)(210+16p)

\frac{d}{d p} (210 + 16 p)

16

Solution steps

\frac{d}{d p} (210 + 16 p)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d p} (210) + \frac{d}{d p} (16 p)

\frac{d}{d p} (210) = 0

\frac{d}{d p} (16 p) = 16

= 0 + 16

Simplify

= 16

y = (x^{2} + 1) \cdot (x + 1)

\frac{( 2 + x )}{( 2 - x )}

arctan (x^{2} + 1)

y = \frac{( x - 3 ) ^{2} - 4}{x ^{2} + 2}

\frac{y ^{2}}{x}