What is the derivative of arctan(x^2+1) ?

The derivative of arctan(x^2+1) is (2x)/(x^4+2x^2+2)

What is the first derivative of arctan(x^2+1) ?

The first derivative of arctan(x^2+1) is (2x)/(x^4+2x^2+2)

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derivative of

arctan (x^{2} + 1)

\frac{2 x}{x ^{4} + 2 x ^{2} + 2}

Solution steps

\frac{d}{d x} (arctan (x^{2} + 1))

Apply the chain rule:

\frac{1}{( x ^{2} + 1 ) ^{2} + 1} \frac{d}{d x} (x^{2} + 1)

= \frac{1}{( x ^{2} + 1 ) ^{2} + 1} \frac{d}{d x} (x^{2} + 1)

\frac{d}{d x} (x^{2} + 1) = 2 x

= \frac{1}{( x ^{2} + 1 ) ^{2} + 1} \cdot 2 x

Simplify

\frac{1}{( x ^{2} + 1 ) ^{2} + 1} \cdot 2 x : \frac{2 x}{x ^{4} + 2 x ^{2} + 2}

= \frac{2 x}{x ^{4} + 2 x ^{2} + 2}

y = \frac{( x - 3 ) ^{2} - 4}{x ^{2} + 2}

\frac{y ^{2}}{x}

\frac{x ^{2} - 5}{1 - 3 x ^{2}}

\frac{l ^{3}}{4} k \frac{1}{4}

3 x + y

What is the derivative of arctan(x^2+1) ?
The derivative of arctan(x^2+1) is (2x)/(x^4+2x^2+2)
What is the first derivative of arctan(x^2+1) ?
The first derivative of arctan(x^2+1) is (2x)/(x^4+2x^2+2)