What is the first derivative of 2i+4j ?

The first derivative of 2i+4j is 4

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derivative of 2i+4j

derivative of

2 i + 4 j

4

Solution steps

\frac{d}{d j} (2 i + 4 j)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d j} (2 i) + \frac{d}{d j} (4 j)

\frac{d}{d j} (2 i) = 0

\frac{d}{d j} (4 j) = 4

= 0 + 4

Simplify

= 4

y = (x + 1)^{2} (x^{2} - 1)

ln (1 + x^{4})

\frac{d}{d x} ((lo g_{10} (6) \cdot x^{2})^{3})

(3 x^{2} - 5 x)^{45}

cos (2 x + 3)