What is the derivative of ln(1+x^4) ?

The derivative of ln(1+x^4) is (4x^3)/(1+x^4)

What is the first derivative of ln(1+x^4) ?

The first derivative of ln(1+x^4) is (4x^3)/(1+x^4)

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derivative of

ln (1 + x^{4})

\frac{4 x ^{3}}{1 + x ^{4}}

Solution steps

\frac{d}{d x} (ln (1 + x^{4}))

Apply the chain rule:

\frac{1}{1 + x ^{4}} \frac{d}{d x} (1 + x^{4})

= \frac{1}{1 + x ^{4}} \frac{d}{d x} (1 + x^{4})

\frac{d}{d x} (1 + x^{4}) = 4 x^{3}

= \frac{1}{1 + x ^{4}} \cdot 4 x^{3}

Simplify

\frac{1}{1 + x ^{4}} \cdot 4 x^{3} : \frac{4 x ^{3}}{1 + x ^{4}}

= \frac{4 x ^{3}}{1 + x ^{4}}

\frac{d}{d x} ((lo g_{10} (6) \cdot x^{2})^{3})

(3 x^{2} - 5 x)^{45}

cos (2 x + 3)

(\frac{x}{3})^{2}

6 cos (x) + sin^{2} (x)

What is the derivative of ln(1+x^4) ?
The derivative of ln(1+x^4) is (4x^3)/(1+x^4)
What is the first derivative of ln(1+x^4) ?
The first derivative of ln(1+x^4) is (4x^3)/(1+x^4)