What is the derivative of (x^2)/(16) ?

The derivative of (x^2)/(16) is x/8

What is the first derivative of (x^2)/(16) ?

The first derivative of (x^2)/(16) is x/8

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derivative of

\frac{x ^{2}}{16}

\frac{x}{8}

Solution steps

\frac{d}{d x} (\frac{x ^{2}}{16})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{16} \frac{d}{d x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{16} \cdot 2 x^{2 - 1}

Simplify

\frac{1}{16} \cdot 2 x^{2 - 1} : \frac{x}{8}

= \frac{x}{8}

\frac{( 1 + x )}{x}

b (1 - sin (x))

cot (x^{2} sin^{2} (x))

a^{3}

y = (\frac{x + 2}{x}) (\frac{x ^{2} - 1}{x})

What is the derivative of (x^2)/(16) ?
The derivative of (x^2)/(16) is x/8
What is the first derivative of (x^2)/(16) ?
The first derivative of (x^2)/(16) is x/8