What is the d/(df)(f(0)+f(-1)*f(2)) ?

The d/(df)(f(0)+f(-1)*f(2)) is -4f

What is the first d/(df)(f(0)+f(-1)*f(2)) ?

The first d/(df)(f(0)+f(-1)*f(2)) is -4f

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\frac{d}{df} (f (0) + f (- 1) \cdot f (2))

- 4 f

Solution steps

\frac{d}{df} (f (0) + f (- 1) f (2))

Simplify

f (0) + f (- 1) f (2) : - 2 f^{2}

= \frac{d}{df} (- 2 f^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 2 \frac{d}{df} (f^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 2 \cdot 2 f^{2 - 1}

Simplify

= - 4 f

y = (3 - x^{2}) (x^{3} - x + 1)

sec^{2} (x) tan (x)

(x^{3} - 1)^{3}

\frac{sin ( x )}{x ^{2}}

e^{2} + (sec (x) x)

What is the d/(df)(f(0)+f(-1)*f(2)) ?
The d/(df)(f(0)+f(-1)*f(2)) is -4f
What is the first d/(df)(f(0)+f(-1)*f(2)) ?
The first d/(df)(f(0)+f(-1)*f(2)) is -4f