What is the derivative of x^2+2x-18 ?

The derivative of x^2+2x-18 is 2x+2

What is the first derivative of x^2+2x-18 ?

The first derivative of x^2+2x-18 is 2x+2

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derivative of

x^{2} + 2 x - 18

2 x + 2

Solution steps

\frac{d}{d x} (x^{2} + 2 x - 18)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (2 x) - \frac{d}{d x} (18)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (18) = 0

= 2 x + 2 - 0

Simplify

= 2 x + 2

x (lo g_{10} (∣ x ∣) - 1)

y = \frac{2 sin ( x )}{5}

x^{\frac{- 1}{2}}

\frac{x ^{3} + 1}{x ^{2}}

(e^{x} + e^{- x})^{2}

What is the derivative of x^2+2x-18 ?
The derivative of x^2+2x-18 is 2x+2
What is the first derivative of x^2+2x-18 ?
The first derivative of x^2+2x-18 is 2x+2