What is the derivative of (e^x+e^{-x})^2 ?

The derivative of (e^x+e^{-x})^2 is 2(e^x+e^{-x})(e^x-e^{-x})

What is the first derivative of (e^x+e^{-x})^2 ?

The first derivative of (e^x+e^{-x})^2 is 2(e^x+e^{-x})(e^x-e^{-x})

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derivative of

(e^{x} + e^{- x})^{2}

2 (e^{x} + e^{- x}) (e^{x} - e^{- x})

Solution steps

\frac{d}{d x} ((e^{x} + e^{- x})^{2})

Apply the chain rule:

2 (e^{x} + e^{- x}) \frac{d}{d x} (e^{x} + e^{- x})

= 2 (e^{x} + e^{- x}) \frac{d}{d x} (e^{x} + e^{- x})

\frac{d}{d x} (e^{x} + e^{- x}) = e^{x} - e^{- x}

= 2 (e^{x} + e^{- x}) (e^{x} - e^{- x})

3^{x} - e^{x} + 5^{x} \cdot ln (x) + 3^{3}

(x + 7)^{5}

y = \frac{( x ^{2} + 2 x + 1 )}{( x + 1 )}

y = x^{4} + 12 x

\frac{d}{d a} (tan^{2} (a) + sin (a) csc (a))

What is the derivative of (e^x+e^{-x})^2 ?
The derivative of (e^x+e^{-x})^2 is 2(e^x+e^{-x})(e^x-e^{-x})
What is the first derivative of (e^x+e^{-x})^2 ?
The first derivative of (e^x+e^{-x})^2 is 2(e^x+e^{-x})(e^x-e^{-x})