What is the derivative of y=x^4+12x ?

The derivative of y=x^4+12x is 4x^3+12

What is the first derivative of y=x^4+12x ?

The first derivative of y=x^4+12x is 4x^3+12

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derivative of

y = x^{4} + 12 x

4 x^{3} + 12

Solution steps

\frac{d}{d x} (x^{4} + 12 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) + \frac{d}{d x} (12 x)

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (12 x) = 12

= 4 x^{3} + 12

\frac{( 3 x ^{2} + x )}{( 3 x ^{2} - x )}

(x^{2} - x + 1) e^{3} x

y = 6 x^{2} - 3 x^{3}

y = (5 x - 3) (\frac{4 x - 3}{x})

\frac{- 5}{( 4 x - 2 y + 2 )}

What is the derivative of y=x^4+12x ?
The derivative of y=x^4+12x is 4x^3+12
What is the first derivative of y=x^4+12x ?
The first derivative of y=x^4+12x is 4x^3+12