What is the d/(da)(tan^2(a)+sin(a)csc(a)) ?

The d/(da)(tan^2(a)+sin(a)csc(a)) is 2sec^2(a)tan(a)

What is the first d/(da)(tan^2(a)+sin(a)csc(a)) ?

The first d/(da)(tan^2(a)+sin(a)csc(a)) is 2sec^2(a)tan(a)

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\frac{d}{d a} (tan^{2} (a) + sin (a) csc (a))

2 sec^{2} (a) tan (a)

Solution steps

\frac{d}{d a} (tan^{2} (a) + sin (a) csc (a))

Simplify

tan^{2} (a) + sin (a) csc (a) : sec^{2} (a)

= \frac{d}{d a} (sec^{2} (a))

Apply the chain rule:

2 sec (a) \frac{d}{d a} (sec (a))

= 2 sec (a) \frac{d}{d a} (sec (a))

\frac{d}{d a} (sec (a)) = sec (a) tan (a)

= 2 sec (a) sec (a) tan (a)

Simplify

2 sec (a) sec (a) tan (a) : 2 sec^{2} (a) tan (a)

= 2 sec^{2} (a) tan (a)

\frac{( 3 x ^{2} + x )}{( 3 x ^{2} - x )}

(x^{2} - x + 1) e^{3} x

y = 6 x^{2} - 3 x^{3}

\frac{d}{d x} ((a \cdot x^{7} \cdot b)^{3})

y = (5 x - 3) (\frac{4 x - 3}{x})

What is the d/(da)(tan^2(a)+sin(a)csc(a)) ?
The d/(da)(tan^2(a)+sin(a)csc(a)) is 2sec^2(a)tan(a)
What is the first d/(da)(tan^2(a)+sin(a)csc(a)) ?
The first d/(da)(tan^2(a)+sin(a)csc(a)) is 2sec^2(a)tan(a)