What is the d/(dt)(0.3cos(30t)) ?

The d/(dt)(0.3cos(30t)) is -9sin(30t)

What is the first d/(dt)(0.3cos(30t)) ?

The first d/(dt)(0.3cos(30t)) is -9sin(30t)

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\frac{d}{d t} (0.3 cos (30 t))

- 9 sin (30 t)

Solution steps

\frac{d}{d t} (0.3 cos (30 t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 0.3 \frac{d}{d t} (cos (30 t))

Apply the chain rule:

- sin (30 t) \frac{d}{d t} (30 t)

= - sin (30 t) \frac{d}{d t} (30 t)

\frac{d}{d t} (30 t) = 30

= 0.3 (- sin (30 t) \cdot 30)

Simplify

= - 9 sin (30 t)

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(a^{x})^{2}

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What is the d/(dt)(0.3cos(30t)) ?
The d/(dt)(0.3cos(30t)) is -9sin(30t)
What is the first d/(dt)(0.3cos(30t)) ?
The first d/(dt)(0.3cos(30t)) is -9sin(30t)