What is the derivative of 1/(8*(-8x-2x)) ?

The derivative of 1/(8*(-8x-2x)) is 1/(66x^2)

What is the first derivative of 1/(8*(-8x-2x)) ?

The first derivative of 1/(8*(-8x-2x)) is 1/(66x^2)

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\frac{d}{d x} (\frac{1}{8 \cdot ( - 8 x ) - 2 x})

\frac{1}{66 x ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{8 ( - 8 x ) - 2 x})

Simplify

\frac{1}{8 ( - 8 x ) - 2 x} : - \frac{1}{66 x}

= \frac{d}{d x} (- \frac{1}{66 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{1}{66} \frac{d}{d x} (\frac{1}{x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= - \frac{1}{66} \frac{d}{d x} (x^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - \frac{1}{66} (- 1 \cdot x^{- 1 - 1})

Simplify

- \frac{1}{66} (- 1 \cdot x^{- 1 - 1}) : \frac{1}{66 x ^{2}}

= \frac{1}{66 x ^{2}}

(a^{x})^{2}

\frac{sin ^{2} ( x )}{x ^{2}}

\frac{d}{d x} (4 x^{2} - 14 x - 8 a)

csc^{3} (x)

2 x^{2} - x + 1

What is the derivative of 1/(8*(-8x-2x)) ?
The derivative of 1/(8*(-8x-2x)) is 1/(66x^2)
What is the first derivative of 1/(8*(-8x-2x)) ?
The first derivative of 1/(8*(-8x-2x)) is 1/(66x^2)