What is the derivative of sec^2(2x+1) ?

The derivative of sec^2(2x+1) is 4sec^2(2x+1)tan(2x+1)

What is the first derivative of sec^2(2x+1) ?

The first derivative of sec^2(2x+1) is 4sec^2(2x+1)tan(2x+1)

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derivative of

sec^{2} (2 x + 1)

4 sec^{2} (2 x + 1) tan (2 x + 1)

Solution steps

\frac{d}{d x} (sec^{2} (2 x + 1))

Apply the chain rule:

2 sec (2 x + 1) \frac{d}{d x} (sec (2 x + 1))

= 2 sec (2 x + 1) \frac{d}{d x} (sec (2 x + 1))

\frac{d}{d x} (sec (2 x + 1)) = sec (2 x + 1) tan (2 x + 1) \cdot 2

= 2 sec (2 x + 1) sec (2 x + 1) tan (2 x + 1) \cdot 2

Simplify

2 sec (2 x + 1) sec (2 x + 1) tan (2 x + 1) \cdot 2 : 4 sec^{2} (2 x + 1) tan (2 x + 1)

= 4 sec^{2} (2 x + 1) tan (2 x + 1)

\frac{2}{3} \frac{x ^{4}}{6} + 5 \frac{x ^{4}}{5}

e^{l} o gx + 1

y = (2 t - 3)^{2}

\frac{2 x}{( 1 - x ^{2} ) ^{2}}

10 + x

What is the derivative of sec^2(2x+1) ?
The derivative of sec^2(2x+1) is 4sec^2(2x+1)tan(2x+1)
What is the first derivative of sec^2(2x+1) ?
The first derivative of sec^2(2x+1) is 4sec^2(2x+1)tan(2x+1)