What is the derivative of 1+ln(x^2) ?

The derivative of 1+ln(x^2) is 2/x

What is the first derivative of 1+ln(x^2) ?

The first derivative of 1+ln(x^2) is 2/x

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derivative of

1 + ln (x^{2})

\frac{2}{x}

Solution steps

\frac{d}{d x} (1 + ln (x^{2}))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (ln (x^{2}))

\frac{d}{d x} (1) = 0

\frac{d}{d x} (ln (x^{2})) = \frac{2}{x}

= 0 + \frac{2}{x}

Simplify

= \frac{2}{x}

13 x^{2} + 26 x + 15

2 x - y + 1

2 x - y

t \cdot lo g_{10} (2 t)

2 t^{2} e^{- t}

What is the derivative of 1+ln(x^2) ?
The derivative of 1+ln(x^2) is 2/x
What is the first derivative of 1+ln(x^2) ?
The first derivative of 1+ln(x^2) is 2/x