What is the derivative of y=x(3-4x) ?

The derivative of y=x(3-4x) is 3-8x

What is the first derivative of y=x(3-4x) ?

The first derivative of y=x(3-4x) is 3-8x

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derivative of

y = x (3 - 4 x)

3 - 8 x

Solution steps

\frac{d}{d x} (x (3 - 4 x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = 3 - 4 x

= \frac{d x}{d x} (3 - 4 x) + \frac{d}{d x} (3 - 4 x) x

\frac{d x}{d x} = 1

\frac{d}{d x} (3 - 4 x) = - 4

= 1 \cdot (3 - 4 x) + (- 4) x

Simplify

= 3 - 8 x

x^{2} - y^{2}

\frac{1}{( x + 2 ) ^{2}}

\frac{( x - m ^{2} )}{( x + 1 )}

\frac{d}{d t} (5 - 6 t + t^{2})

\frac{d}{d t} (3 e^{s i n (0.5 t)} - 4)

What is the derivative of y=x(3-4x) ?
The derivative of y=x(3-4x) is 3-8x
What is the first derivative of y=x(3-4x) ?
The first derivative of y=x(3-4x) is 3-8x