What is the first derivative of 2y+1 ?

The first derivative of 2y+1 is 2

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derivative of 2y+1

derivative of

2 y + 1

2

Solution steps

\frac{d}{d y} (2 y + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d y} (2 y) + \frac{d}{d y} (1)

\frac{d}{d y} (2 y) = 2

\frac{d}{d y} (1) = 0

= 2 + 0

Simplify

= 2

\frac{e ^{x}}{( 1 - e ^{x} )}

30 + 40 e^{0.0098} t

y = 13 x^{2} + 8 x - 9

y = \frac{- x ^{2}}{2}

(2 x^{2})^{- 1}