What is the derivative of y=13x^2+8x-9 ?

The derivative of y=13x^2+8x-9 is 26x+8

What is the first derivative of y=13x^2+8x-9 ?

The first derivative of y=13x^2+8x-9 is 26x+8

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derivative of

y = 13 x^{2} + 8 x - 9

26 x + 8

Solution steps

\frac{d}{d x} (13 x^{2} + 8 x - 9)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (13 x^{2}) + \frac{d}{d x} (8 x) - \frac{d}{d x} (9)

\frac{d}{d x} (13 x^{2}) = 26 x

\frac{d}{d x} (8 x) = 8

\frac{d}{d x} (9) = 0

= 26 x + 8 - 0

Simplify

= 26 x + 8

y = \frac{- x ^{2}}{2}

(2 x^{2})^{- 1}

\frac{d}{d a} (\frac{a}{b - 3})

\frac{tan ( x )}{( x + 3 )}

\frac{d}{d x} (5 cos (x) + ln (x))

What is the derivative of y=13x^2+8x-9 ?
The derivative of y=13x^2+8x-9 is 26x+8
What is the first derivative of y=13x^2+8x-9 ?
The first derivative of y=13x^2+8x-9 is 26x+8