What is the derivative of 5cos(x+ln(x)) ?

The derivative of 5cos(x+ln(x)) is -5sin(x)+1/x

What is the first derivative of 5cos(x+ln(x)) ?

The first derivative of 5cos(x+ln(x)) is -5sin(x)+1/x

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\frac{d}{d x} (5 cos (x) + ln (x))

- 5 sin (x) + \frac{1}{x}

Solution steps

\frac{d}{d x} (5 cos (x) + ln (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (5 cos (x)) + \frac{d}{d x} (ln (x))

\frac{d}{d x} (5 cos (x)) = - 5 sin (x)

\frac{d}{d x} (ln (x)) = \frac{1}{x}

= - 5 sin (x) + \frac{1}{x}

100 + 5 q^{2}

\frac{d}{d j} (12 i - 19 j)

(\frac{1}{1 + x})^{- 1}

y = 4 sec (2 x)

\frac{( x ^{2} + 1 )}{2}

What is the derivative of 5cos(x+ln(x)) ?
The derivative of 5cos(x+ln(x)) is -5sin(x)+1/x
What is the first derivative of 5cos(x+ln(x)) ?
The first derivative of 5cos(x+ln(x)) is -5sin(x)+1/x