What is the derivative of 3x^2-(k+2x+k-1) ?

The derivative of 3x^2-(k+2x+k-1) is 6x-k-2

What is the first derivative of 3x^2-(k+2x+k-1) ?

The first derivative of 3x^2-(k+2x+k-1) is 6x-k-2

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\frac{d}{d x} (3 x^{2} - (k + 2) x + k - 1)

6 x - k - 2

Solution steps

\frac{d}{d x} (3 x^{2} - (k + 2) x + k - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} ((k + 2) x) + \frac{d k}{d x} - \frac{d}{d x} (1)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} ((k + 2) x) = k + 2

\frac{d k}{d x} = 0

\frac{d}{d x} (1) = 0

= 6 x - (k + 2) + 0 - 0

Simplify

= 6 x - k - 2

y = - 50

x^{\frac{- 1}{3}}

(\frac{x ^{3}}{3}) - (\frac{x ^{2}}{2}) - 2 x

\frac{d}{d q} (1 + q^{2})

(1 - x)^{4}

What is the derivative of 3x^2-(k+2x+k-1) ?
The derivative of 3x^2-(k+2x+k-1) is 6x-k-2
What is the first derivative of 3x^2-(k+2x+k-1) ?
The first derivative of 3x^2-(k+2x+k-1) is 6x-k-2