What is the derivative of ((x^3)/3)-((x^2)/2)-2x ?

The derivative of ((x^3)/3)-((x^2)/2)-2x is x^2-x-2

What is the first derivative of ((x^3)/3)-((x^2)/2)-2x ?

The first derivative of ((x^3)/3)-((x^2)/2)-2x is x^2-x-2

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derivative of

(\frac{x ^{3}}{3}) - (\frac{x ^{2}}{2}) - 2 x

x^{2} - x - 2

Solution steps

\frac{d}{d x} (\frac{x ^{3}}{3} - \frac{x ^{2}}{2} - 2 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x ^{3}}{3}) - \frac{d}{d x} (\frac{x ^{2}}{2}) - \frac{d}{d x} (2 x)

\frac{d}{d x} (\frac{x ^{3}}{3}) = x^{2}

\frac{d}{d x} (\frac{x ^{2}}{2}) = x

\frac{d}{d x} (2 x) = 2

= x^{2} - x - 2

\frac{d}{d q} (1 + q^{2})

(1 - x)^{4}

\frac{d}{d o} (m o d x^{2})

y = (3 + 2 x^{2})^{4}

5^{2 x^{2} + x + 1}

What is the derivative of ((x^3)/3)-((x^2)/2)-2x ?
The derivative of ((x^3)/3)-((x^2)/2)-2x is x^2-x-2
What is the first derivative of ((x^3)/3)-((x^2)/2)-2x ?
The first derivative of ((x^3)/3)-((x^2)/2)-2x is x^2-x-2