What is the derivative of (1+x^2)^3 ?

The derivative of (1+x^2)^3 is 6x(1+x^2)^2

What is the first derivative of (1+x^2)^3 ?

The first derivative of (1+x^2)^3 is 6x(1+x^2)^2

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derivative of

(1 + x^{2})^{3}

6 x (1 + x^{2})^{2}

Solution steps

\frac{d}{d x} ((1 + x^{2})^{3})

Apply the chain rule:

3 (1 + x^{2})^{2} \frac{d}{d x} (1 + x^{2})

= 3 (1 + x^{2})^{2} \frac{d}{d x} (1 + x^{2})

\frac{d}{d x} (1 + x^{2}) = 2 x

= 3 (1 + x^{2})^{2} \cdot 2 x

Simplify

= 6 x (1 + x^{2})^{2}

sin^{22} (x)

\frac{1500}{x}

y = \frac{1}{2 x}

10 0^{200} x

3 x^{6} ln (3 x^{3})

What is the derivative of (1+x^2)^3 ?
The derivative of (1+x^2)^3 is 6x(1+x^2)^2
What is the first derivative of (1+x^2)^3 ?
The first derivative of (1+x^2)^3 is 6x(1+x^2)^2