What is the derivative of 2a^x ?

The derivative of 2a^x is 2a^xln(a)

What is the first derivative of 2a^x ?

The first derivative of 2a^x is 2a^xln(a)

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derivative of

2 a^{x}

2 a^{x} ln (a)

Solution steps

\frac{d}{d x} (2 a^{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (a^{x})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= 2 a^{x} ln (a)

(4 x^{5} + 1)^{3}

cos (x^{2} + 9)

\frac{d}{d x} (2 x^{3} - 16 x^{2} - 2 c + 4 d)

g (x) = 3^{2 x + 7}

(x + 5)^{6} \cdot (x^{2} + 2)^{5}

What is the derivative of 2a^x ?
The derivative of 2a^x is 2a^xln(a)
What is the first derivative of 2a^x ?
The first derivative of 2a^x is 2a^xln(a)