What is the derivative of cos(x^2+9) ?

The derivative of cos(x^2+9) is -sin(x^2+9)*2x

What is the first derivative of cos(x^2+9) ?

The first derivative of cos(x^2+9) is -sin(x^2+9)*2x

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derivative of

cos (x^{2} + 9)

- sin (x^{2} + 9) \cdot 2 x

Solution steps

\frac{d}{d x} (cos (x^{2} + 9))

Apply the chain rule:

- sin (x^{2} + 9) \frac{d}{d x} (x^{2} + 9)

= - sin (x^{2} + 9) \frac{d}{d x} (x^{2} + 9)

\frac{d}{d x} (x^{2} + 9) = 2 x

= - sin (x^{2} + 9) \cdot 2 x

\frac{d}{d x} (2 x^{3} - 16 x^{2} - 2 c + 4 d)

g (x) = 3^{2 x + 7}

(x + 5)^{6} \cdot (x^{2} + 2)^{5}

1 + 2 sin^{2} (x)

\frac{x}{( x ^{2} + y ^{2} )}

What is the derivative of cos(x^2+9) ?
The derivative of cos(x^2+9) is -sin(x^2+9)*2x
What is the first derivative of cos(x^2+9) ?
The first derivative of cos(x^2+9) is -sin(x^2+9)*2x