What is the derivative of 1+2sin^2(x) ?

The derivative of 1+2sin^2(x) is 2sin(2x)

What is the first derivative of 1+2sin^2(x) ?

The first derivative of 1+2sin^2(x) is 2sin(2x)

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derivative of

1 + 2 sin^{2} (x)

2 sin (2 x)

Solution steps

\frac{d}{d x} (1 + 2 sin^{2} (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (2 sin^{2} (x))

\frac{d}{d x} (1) = 0

\frac{d}{d x} (2 sin^{2} (x)) = 2 sin (2 x)

= 0 + 2 sin (2 x)

Simplify

= 2 sin (2 x)

\frac{x}{( x ^{2} + y ^{2} )}

x^{3} - 3 x^{2} - 20

(3 x + 1)^{3}

\frac{d}{d x} (- x^{2} + 3 x + k)

y = (x^{- 2}) ln (x)

What is the derivative of 1+2sin^2(x) ?
The derivative of 1+2sin^2(x) is 2sin(2x)
What is the first derivative of 1+2sin^2(x) ?
The first derivative of 1+2sin^2(x) is 2sin(2x)