What is the derivative of ((1+1)/x)^2 ?

The derivative of ((1+1)/x)^2 is -8/(x^3)

What is the first derivative of ((1+1)/x)^2 ?

The first derivative of ((1+1)/x)^2 is -8/(x^3)

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derivative of

(\frac{1 + 1}{x})^{2}

- \frac{8}{x ^{3}}

Solution steps

\frac{d}{d x} ((\frac{1 + 1}{x})^{2})

Apply the chain rule:

2 \cdot \frac{1 + 1}{x} \frac{d}{d x} (\frac{1 + 1}{x})

= 2 \cdot \frac{1 + 1}{x} \frac{d}{d x} (\frac{1 + 1}{x})

\frac{d}{d x} (\frac{1 + 1}{x}) = - \frac{2}{x ^{2}}

= 2 \cdot \frac{1 + 1}{x} (- \frac{2}{x ^{2}})

Simplify

2 \cdot \frac{1 + 1}{x} (- \frac{2}{x ^{2}}) : - \frac{8}{x ^{3}}

= - \frac{8}{x ^{3}}

y = x^{3} + x^{2} + 1

y = \frac{x ^{3}}{3} - 5 \frac{x ^{2}}{2} + 6 x - 4

y = \frac{2 ^{x}}{3 ^{x}}

\frac{d}{d t} (40 - 8 t)

x^{2} \cdot 1 + x^{2}

What is the derivative of ((1+1)/x)^2 ?
The derivative of ((1+1)/x)^2 is -8/(x^3)
What is the first derivative of ((1+1)/x)^2 ?
The first derivative of ((1+1)/x)^2 is -8/(x^3)