What is the derivative of y=(6x-3)(3x+9) ?

The derivative of y=(6x-3)(3x+9) is 36x+45

What is the first derivative of y=(6x-3)(3x+9) ?

The first derivative of y=(6x-3)(3x+9) is 36x+45

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derivative of

y = (6 x - 3) (3 x + 9)

36 x + 45

Solution steps

\frac{d}{d x} ((6 x - 3) (3 x + 9))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = 6 x - 3, g = 3 x + 9

= \frac{d}{d x} (6 x - 3) (3 x + 9) + \frac{d}{d x} (3 x + 9) (6 x - 3)

\frac{d}{d x} (6 x - 3) = 6

\frac{d}{d x} (3 x + 9) = 3

= 6 (3 x + 9) + 3 (6 x - 3)

Simplify

6 (3 x + 9) + 3 (6 x - 3) : 36 x + 45

= 36 x + 45

\frac{d}{d t} (100 + 10 t + 1.25 t)

y = \frac{arcsin ( 1 )}{x}

\frac{( 1 - x ) x ^{2}}{( 1 + x ^{2} )}

\frac{d}{d x} ((x + z) (x - 5)^{8})

\frac{e ^{x}}{3}

What is the derivative of y=(6x-3)(3x+9) ?
The derivative of y=(6x-3)(3x+9) is 36x+45
What is the first derivative of y=(6x-3)(3x+9) ?
The first derivative of y=(6x-3)(3x+9) is 36x+45