What is the derivative of f(x)=log_{2}(x)-1 ?

The derivative of f(x)=log_{2}(x)-1 is 1/(ln(2)x)

What is the first derivative of f(x)=log_{2}(x)-1 ?

The first derivative of f(x)=log_{2}(x)-1 is 1/(ln(2)x)

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derivative of

f (x) = lo g_{2} (x) - 1

\frac{1}{ln ( 2 ) x}

Solution steps

\frac{d}{d x} (lo g_{2} (x) - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (lo g_{2} (x)) - \frac{d}{d x} (1)

\frac{d}{d x} (lo g_{2} (x)) = \frac{1}{x ln ( 2 )}

\frac{d}{d x} (1) = 0

= \frac{1}{x ln ( 2 )} - 0

Simplify

= \frac{1}{ln ( 2 ) x}

12 cos^{2} (t)

\frac{1}{x ( x ^{2} + e ^{x} )}

cos (\frac{x}{x + 1})

1 + 2 x y

2 x + cot (x)

What is the derivative of f(x)=log_{2}(x)-1 ?
The derivative of f(x)=log_{2}(x)-1 is 1/(ln(2)x)
What is the first derivative of f(x)=log_{2}(x)-1 ?
The first derivative of f(x)=log_{2}(x)-1 is 1/(ln(2)x)