What is the derivative of 2x+cot(x) ?

The derivative of 2x+cot(x) is 2-csc^2(x)

What is the first derivative of 2x+cot(x) ?

The first derivative of 2x+cot(x) is 2-csc^2(x)

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derivative of

2 x + cot (x)

2 - csc^{2} (x)

Solution steps

\frac{d}{d x} (2 x + cot (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x) + \frac{d}{d x} (cot (x))

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (cot (x)) = - csc^{2} (x)

= 2 - csc^{2} (x)

sin^{2} (x) + tan^{3} (x)

\frac{d}{d t} \frac{500}{( t + 2 )} - \frac{1000}{( ( t + 2 ) ^{2} )}

\frac{x ^{2}}{( e ^{x} - 1 ) ^{2}}

f (x) = \frac{( 0.8 - 0.3 x )}{x}

x^{3} + 4 x^{2} + 3

What is the derivative of 2x+cot(x) ?
The derivative of 2x+cot(x) is 2-csc^2(x)
What is the first derivative of 2x+cot(x) ?
The first derivative of 2x+cot(x) is 2-csc^2(x)