What is the derivative of x^3+4x^2+3 ?

The derivative of x^3+4x^2+3 is 3x^2+8x

What is the first derivative of x^3+4x^2+3 ?

The first derivative of x^3+4x^2+3 is 3x^2+8x

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derivative of

x^{3} + 4 x^{2} + 3

3 x^{2} + 8 x

Solution steps

\frac{d}{d x} (x^{3} + 4 x^{2} + 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (4 x^{2}) + \frac{d}{d x} (3)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (4 x^{2}) = 8 x

\frac{d}{d x} (3) = 0

= 3 x^{2} + 8 x + 0

Simplify

= 3 x^{2} + 8 x

\frac{d}{d a} (cos^{4} (a) + sin^{4} (a))

y = \frac{x ^{3} - x}{x + 1}

y = \frac{1}{( x + 2 )}

\frac{x ^{7}}{7} + \frac{x ^{5}}{5} \frac{x ^{3}}{3} + x

5 cos^{2} (3 x)

What is the derivative of x^3+4x^2+3 ?
The derivative of x^3+4x^2+3 is 3x^2+8x
What is the first derivative of x^3+4x^2+3 ?
The first derivative of x^3+4x^2+3 is 3x^2+8x