What is the derivative of y= 1/(5x) ?

The derivative of y= 1/(5x) is -1/(5x^2)

What is the first derivative of y= 1/(5x) ?

The first derivative of y= 1/(5x) is -1/(5x^2)

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derivative of

y = \frac{1}{5 x}

- \frac{1}{5 x ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{5 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{5} \frac{d}{d x} (\frac{1}{x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{1}{5} \frac{d}{d x} (x^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{5} (- 1 \cdot x^{- 1 - 1})

Simplify

\frac{1}{5} (- 1 \cdot x^{- 1 - 1}) : - \frac{1}{5 x ^{2}}

= - \frac{1}{5 x ^{2}}

ln (n + 1)

\frac{d}{d o} (7 o + (- 18) 0 - 61 + (- 9) 1)

1 - a

\frac{2}{( x ^{2} - 1 )}

f (x) = 4 x^{5} - 5 x^{4}

What is the derivative of y= 1/(5x) ?
The derivative of y= 1/(5x) is -1/(5x^2)
What is the first derivative of y= 1/(5x) ?
The first derivative of y= 1/(5x) is -1/(5x^2)