What is the derivative of ln(n+1) ?

The derivative of ln(n+1) is 1/(n+1)

What is the first derivative of ln(n+1) ?

The first derivative of ln(n+1) is 1/(n+1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

ln (n + 1)

\frac{1}{n + 1}

Solution steps

\frac{d}{d n} (ln (n + 1))

Apply the chain rule:

\frac{1}{n + 1} \frac{d}{d n} (n + 1)

= \frac{1}{n + 1} \frac{d}{d n} (n + 1)

\frac{d}{d n} (n + 1) = 1

= \frac{1}{n + 1} \cdot 1

Simplify

= \frac{1}{n + 1}

\frac{d}{d o} (7 o + (- 18) 0 - 61 + (- 9) 1)

1 - a

\frac{2}{( x ^{2} - 1 )}

f (x) = 4 x^{5} - 5 x^{4}

lo g_{10} (\frac{1}{x ^{2}})

What is the derivative of ln(n+1) ?
The derivative of ln(n+1) is 1/(n+1)
What is the first derivative of ln(n+1) ?
The first derivative of ln(n+1) is 1/(n+1)