What is the d/(do)(7o+(-18)0-61+(-9)1) ?

The d/(do)(7o+(-18)0-61+(-9)1) is 7

What is the first d/(do)(7o+(-18)0-61+(-9)1) ?

The first d/(do)(7o+(-18)0-61+(-9)1) is 7

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\frac{d}{d o} (7 o + (- 18) 0 - 61 + (- 9) 1)

7

Solution steps

\frac{d}{d o} (7 o + (- 18) \cdot 0 - 61 + (- 9) \cdot 1)

Simplify

7 o + (- 18) \cdot 0 - 61 + (- 9) \cdot 1 : 7 o - 70

= \frac{d}{d o} (7 o - 70)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d o} (7 o) - \frac{d}{d o} (70)

\frac{d}{d o} (7 o) = 7

\frac{d}{d o} (70) = 0

= 7 - 0

Simplify

= 7

1 - a

\frac{2}{( x ^{2} - 1 )}

f (x) = 4 x^{5} - 5 x^{4}

lo g_{10} (\frac{1}{x ^{2}})

sin^{2} (2 x + 0.5)

What is the d/(do)(7o+(-18)0-61+(-9)1) ?
The d/(do)(7o+(-18)0-61+(-9)1) is 7
What is the first d/(do)(7o+(-18)0-61+(-9)1) ?
The first d/(do)(7o+(-18)0-61+(-9)1) is 7